- #1
Blocker12
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Homework Statement
A car that weights 600kg, traveling at 300km/hr and the coefficient of static friction between the car and the road is 1.5, down force is equal to 2.6v^2 and air resistance is 1.5v^2 (v is in m/s). Calculate how many meters it would take for the car to stop with the breaks applied to there maximum value.
Homework Equations
V(final) = V(initial) + at
Work = -1/2mv^2
I'm not sure if there are more?
The Attempt at a Solution
N(normal force)= mg + 2.6v^2 when v = 83.3 (300km/hr converted to m/s)
N= 23921.1N
F(friction)= 1.5 * N
= 32881.7N
F(air resistance)= 1.5v^2 when v= 83.3
=10408.3N
Finding the acceleration of the forces
a= F/m
Total accelection = -77.3m/s^2
How long it takes to go from 300 to 0 [/B]
0=83.3-77.3*t
t=1.1sec
Integration of velocity formula to get the displacement formula
D=83.3*t-(77.2/2)*t^2 when t = 1.1
=44.9m
I feel like the deceleration is way to high (just under 8g) and I'm not sure how I'm to correct that as I feel like I have used formula incorrectly as doing from 300km/hr to 0 in just over a second can't be right,
so any help I can get to point me in the right direction would be greatly appreciated.
Thank You for your time