- #1
Bashyboy
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Homework Statement
A synchronous satellite, which always remains above the same point on a planet's equator, is put in orbit around Jupiter to study that planet's famous red spot. Jupiter rotates once every 9.84 h. Use the following data to find the altitude of the satellite above the surface of the planet. Jupiter has a mass of [itex]1.90 \cdot 10^{27}~kg[/itex], and a mean radius of [itex]6.99 \cdot 10^{7}~m[/itex].
Homework Equations
[itex]v= \large \sqrt{ \frac{GM_j}{R_j + h}}[/itex] [itex]M_j[/itex] mass of Jupiter; [itex]R_j[/itex] average radius of Jupiter.
[itex]v= \large \sqrt{ \frac{GM_j}{r}}[/itex]
[itex]v_{tan}=r\omega[/itex]
The Attempt at a Solution
I know that in order for the satellite to continually be suspended above the same spot on Jupiter, they have to be rotating through the same angles and take the amount of time to rotate through those angles. Hence, [itex]\omega_j=\omega_s= \frac{2\pi}{35424~s}[/itex] (I converted the hours to seconds).
I thought of using the first forumula; but when I substituted
[itex]v_{tan}=r\omega[/itex] and tried to solve for r, it became rather difficult. And so, I opted to use the second equation and perform the same steps. I solved for [itex]r[/itex], [itex]r= (\large \frac{GM_j}{\omega^2})^{1/3}[/itex]
After the final substitution, [itex]r= 1.59 \cdot 10^8 m [/itex]. This, however, isn't the correct answer. What did I do wrong?