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pinkxoxo
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1. THE PROBLEM: A 9 kg monkey climbs up a massless rope that runs over a frictionless tree limb and back down to a 21 kg package on the ground (Fig. 5-54).
Figure 5-54.
(a) What is the magnitude of the least acceleration the monkey must have in order to lift the package off the ground?
m/s2
Assume that after the package has been lifted, the monkey stops its climb and holds onto the rope.
(b) What is the monkey's acceleration?
m/s2
(c) What is the tension in the rope?
N
2.) MY ATTEMPTS: I figured that in order for the monkey to be able to lift the crate its acceleration should be proportional to where the monkey and crate had the same force.
F=ma=m(Monkey(9))(a)=m(Crate(21))(9.8)
a=22.876 m/s^2...according to web assign I am wrong! I can solve the other parts of the problem if I knew how to find the first acceleration
PLEASE HELP :)
Figure 5-54.
(a) What is the magnitude of the least acceleration the monkey must have in order to lift the package off the ground?
m/s2
Assume that after the package has been lifted, the monkey stops its climb and holds onto the rope.
(b) What is the monkey's acceleration?
m/s2
(c) What is the tension in the rope?
N
2.) MY ATTEMPTS: I figured that in order for the monkey to be able to lift the crate its acceleration should be proportional to where the monkey and crate had the same force.
F=ma=m(Monkey(9))(a)=m(Crate(21))(9.8)
a=22.876 m/s^2...according to web assign I am wrong! I can solve the other parts of the problem if I knew how to find the first acceleration
PLEASE HELP :)