I've calculated the velocity upon the objects impact which is 1.476 m/s2Chandra Prayaga said:What have you done so far? The relevant equation that you wrote is wrong.
I really don't know what information I need for the last part that's the issue. I know that the energy used in response to stop the objects will obviously be equal but I've never worked with retarding forces before.Chandra Prayaga said:In all such problems, you should draw a diagram, labeling the different positions. Similarly, label the two balls as A and B. For example, the initial position , with ball A at the top of its path and ball B on the ground can be called position 1. The position just before impact is called 2, and the final position after the two balls sink and come to rest together is called 3.
Your unit for velocity is wrong.
Do you think the kinetic energy in position 2 should be different from the potential energy in position 1?
What information do you need to calculate the last part? How can you get that information?
How about friction?Taidhg said:I've never worked with retarding forces before
I stated in the original post that the object is in free fall. The question is about a pile driver falling onto a pile but I usually ignore those details.gneill said:How about friction?
After the collision occurs, the objects are not in free-fall. The ground is impeding their progress. Friction.Taidhg said:I stated in the original post that the object is in free fall. The question is about a pile driver falling onto a pile but I usually ignore those details.
Please show your calculation.Taidhg said:I've calculated the velocity upon the objects impact which is 1.476 m/s2
Why are they different?Taidhg said:I also have calculated the GPE before it falls which is 1962J and the kinetic energy upon impact which is 1961.33J
The energy taken by the retarding force in bringing them to rest will not be equal to the initial GPE. There is energy lost in the impact itself. Have you worked with impacts before?Taidhg said:the energy used in response to stop the objects will obviously be equal
The formula for calculating retarding force is F = m x a, where F is the force, m is the mass of the object, and a is the acceleration. This formula is also known as Newton's Second Law of Motion.
The mass of an object can be calculated by dividing its weight (in Newtons) by the acceleration due to gravity (9.8 m/s^2). In this case, the mass of the 50kg and 6kg objects would be 50kg = 50N/9.8m/s^2 = 5.1kg and 6kg = 6N/9.8m/s^2 = 0.61kg.
The unit of measurement for retarding force is Newtons (N), which is equivalent to kilograms x meters per second squared (kg*m/s^2).
The acceleration of an object can be determined by using the formula a = F/m, where a is the acceleration, F is the force, and m is the mass of the object. In this case, the acceleration of the 50kg and 6kg objects would be a = 50N/5.1kg = 9.8m/s^2 and a = 6N/0.61kg = 9.8m/s^2.
No, retarding force cannot be calculated without knowing the mass and acceleration of the object. These two variables are necessary components in the formula for calculating retarding force.