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looi76
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[SOLVED] Calculate resistivity of the material of the wire
Question:
[tex]0.75A[/tex] Current flows through an iron wire when a battery of [tex]1.5V[/tex] us connected across its ends. The length of the wire is [tex]5m[/tex] and Area is [tex]2.5 \times 10^{-7} m^2[/tex]. Calculate resistivity of the material of the wire.
Equation:
[tex]R = \frac{Pl}{A}[/tex]
Attempt:
[tex]I = 0.75A \ , \ V = 1.5V \ , \ l = 5m \ , \ A = 2.5 \times 10^{-7} m^2[/tex]
[tex]R = \frac{Pl}{A}[/tex]
[tex]P = IV[/tex]
[tex]P = 0.75 \times 1.5[/tex]
[tex]P = 1.125[/tex]
[tex]R = \frac{1.125 \times 5}{2.5 \times 10^{-7}}[/tex]
[tex]R = 2.3 \times 10^7[/tex]
Is my answer correct?
Question:
[tex]0.75A[/tex] Current flows through an iron wire when a battery of [tex]1.5V[/tex] us connected across its ends. The length of the wire is [tex]5m[/tex] and Area is [tex]2.5 \times 10^{-7} m^2[/tex]. Calculate resistivity of the material of the wire.
Equation:
[tex]R = \frac{Pl}{A}[/tex]
Attempt:
[tex]I = 0.75A \ , \ V = 1.5V \ , \ l = 5m \ , \ A = 2.5 \times 10^{-7} m^2[/tex]
[tex]R = \frac{Pl}{A}[/tex]
[tex]P = IV[/tex]
[tex]P = 0.75 \times 1.5[/tex]
[tex]P = 1.125[/tex]
[tex]R = \frac{1.125 \times 5}{2.5 \times 10^{-7}}[/tex]
[tex]R = 2.3 \times 10^7[/tex]
Is my answer correct?