- #1
Stewart Mala
- 3
- 1
Hi All,
I have an argument to settle. Here's the problem. A gun has two rounds chambered. The first round is a solid copper hollow point, the second round is a normal copper jacketed lead core. Both rounds are the exact same shape and physical dimensions. Both cartridges contain the exact same quantity, quality and type of propellant. The only difference between the two rounds is the mass of each. For argument's sake, the solid copper round is 80 grams, the lead core round is 150 grams. All other parameters are equal.
On firing of each round, assuming one could measure the energy of each round as soon as it left the barrel of the gun, which round contains the most energy and why?
Is it:
a) The solid copper hollow point.
b) The full copper jacket lead core.
c) They both contain the same amount of energy.
Further, how many formulas cover this? Is there a difference between kinetic energy as measured and momentum? Or are they both the same? Should Newton's second law be used in this case, F=MxA, or should you use KE=0.5xmv2 to obtain the amount Kinetic Energy?
Many thanks,
I have an argument to settle. Here's the problem. A gun has two rounds chambered. The first round is a solid copper hollow point, the second round is a normal copper jacketed lead core. Both rounds are the exact same shape and physical dimensions. Both cartridges contain the exact same quantity, quality and type of propellant. The only difference between the two rounds is the mass of each. For argument's sake, the solid copper round is 80 grams, the lead core round is 150 grams. All other parameters are equal.
On firing of each round, assuming one could measure the energy of each round as soon as it left the barrel of the gun, which round contains the most energy and why?
Is it:
a) The solid copper hollow point.
b) The full copper jacket lead core.
c) They both contain the same amount of energy.
Further, how many formulas cover this? Is there a difference between kinetic energy as measured and momentum? Or are they both the same? Should Newton's second law be used in this case, F=MxA, or should you use KE=0.5xmv2 to obtain the amount Kinetic Energy?
Many thanks,