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elemis
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Homework Statement
A solution is prepared by dissolving 0.475g of (NH4)2SO4 in enough of distilled water and the solution is made up to 2.0 dm3
Calculate the ppm of
NH4+
Homework Equations
The Attempt at a Solution
(NH4)2SO4 -----> 2NH4+ + SO42-
0.475/132 = 3.598 *10^-3 moles of Ammonium Sulphate
2*[3.598 *10^-3] = 7.197*10^-3 NH4+ ions
Since concentration = no. of moles / volume
c = 7.197*10^-3 / 2 = 3.598*10^-3 moldm-3
Converting moldm-3 to gdm-3 gives : 0.475 gdm-3
Converting gdm-3 to milligrams per dm3
we get 475 mgdm-3 or 475 ppm
Is this correct ?