Calculate Horizontal Velocity of Jetliner at 233 m/s

[tryton]

Homework Statement

A jetliner is moving at a speed of 233 m/s. The vertical component of the plane's velocity is 66.9 m/s. Determine the magnitude of the horizontal component of the plane's velocity.

The Attempt at a Solution

233m/s^2=66m/s^2+x^2=233.189135m/s
66m/s cos(90)=0

I am not really sure how to find velocity from speed without knowing the angle... It's not given that it is 90... I know this is supposed to be easy but I am a beginner.

Thanks for help

 

[USN2ENG]

Homework Statement

A jetliner is moving at a speed of 233 m/s. The vertical component of the plane's velocity is 66.9 m/s. Determine the magnitude of the horizontal component of the plane's velocity.

The Attempt at a Solution

233m/s^2=66m/s^2+x^2=233.189135m/s
66m/s cos(90)=0

I am not really sure how to find velocity from speed without knowing the angle... It's not given that it is 90... I know this is supposed to be easy but I am a beginner.

Thanks for help

You are almost there:
So its Vx=Vcos(theta)

So then with algebra its: arccosine(Vx/V)=theta...plug in your given numbers..
Theta = 73.3 degrees

Then find the y component with Vy=Vsin(73.3) = 233sin(73.3)=223 so Vy=223m/s

to check this then you would do sqrt(Vx^2+Vy^2)=V

 

[SaltyBriefs]

You are almost there:
So its Vx=Vcos(theta)

So then with algebra its: arccosine(Vx/V^2)=theta...plug in your given numbers..
Theta = 73.3 degrees

Then find the y component with Vy=Vsin(73.3) = 233sin(73.3)=223 so Vy=223m/s

to check this then you would do sqrt(Vx^2+Vy^2)=V

Beat me to it. But yeah do this.

 

[tryton]

Thanks! That was helpful!

 

[rwisz]

ing me with this problem.

I understand your confusion about finding the horizontal velocity without knowing the angle. In order to accurately calculate the horizontal velocity, we need to know both the speed and the angle at which the jetliner is traveling. Without this information, it is not possible to determine the horizontal velocity.

If we assume that the angle of the jetliner's velocity is 90 degrees (horizontal), then we can use trigonometric functions to calculate the horizontal velocity. We can use the Pythagorean theorem to find the magnitude of the total velocity (233 m/s) and the vertical velocity (66.9 m/s).

By using the Pythagorean theorem, we can find the magnitude of the horizontal velocity:
233^2 = (66.9)^2 + x^2
x = √(233^2 - 66.9^2) = 223.5 m/s

Therefore, the horizontal velocity of the jetliner is 223.5 m/s. However, it is important to note that this calculation is based on the assumption that the angle of the jetliner's velocity is 90 degrees. If the angle is different, the horizontal velocity will also be different.

In conclusion, in order to accurately calculate the horizontal velocity of the jetliner, we need to know both the speed and the angle at which it is traveling. Without this information, we cannot accurately determine the horizontal velocity.