Calculate Frictional Force for 800N Force on 100kg Block

[emilyn]

1. A force of 800N parallel to the plane is applied to a 100kg block on the plane to push it up the plane. If the component of the weight down the incline plane is 500 N, what is the frictional force?



2. Frictional force = u.Normal Force



3. Fi = Wx + Ff
Ff = Fi - Wx
Ff = 18 N

 

[tiny-tim]

Welcome to PF!

Frictional force = 1/Normal Force
…
Fi = Wx + Ff
Ff = Fi - Wx
Ff = 18 N[/b]

Hi emilyn! Welcome to PF!

Nooo … frictional force = normal Force times coefficient of friction (µ).

(or µ = frictional force/normal force )

Try again!

 

[baba89]

4. The frictional force can be calculated using the formula Ff = u * N, where u is the coefficient of friction and N is the normal force. In this case, the normal force is equal to the weight of the block, which is 100kg * 9.8m/s^2 = 980N.


5. Since the component of the weight down the incline plane is 500N, the normal force is reduced to 500N. Therefore, the frictional force is Ff = u * 500N.

6. To find the coefficient of friction, we can use the formula u = Ff / N. Plugging in the known values, we get u = 18N / 500N = 0.036.

7. Therefore, the frictional force acting on the block is 18N. This means that there is enough friction between the block and the incline plane to prevent it from sliding down when a force of 800N is applied to push it up the plane.

8. It is important to consider the frictional force in any situation involving motion on an incline plane, as it can greatly affect the overall movement and stability of objects. This calculation allows us to better understand the forces at play and make informed decisions in engineering and other applications.