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beeteep
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Homework Statement
A particle of mass 7.3 × 10−5 g and charge 24 mC moves in a region of space where the electric field is uniform and is 6.3 N/C in the x direction and zero in the y and z direction. If the initial velocity of the particle is given by vy = 4.1 × 105 m/s, vx = vz = 0, what is the speed of the particle at 0.4 s? Answer in units of m/s
Homework Equations
F=ma
F=qE
v=vi + at
The Attempt at a Solution
m=7.3x10-8 kg
q=.024 C
E=6.3 N/C
F = .024(6.3) = .1512 N
.1512 = 7.3x10-8a
a = 2071232.877 m/s2x = doesn't matter
xi = doesn't matter
v = ?
vi = 4.1x10^5
a = 2071232.877
t = .4
v = vi + at
v = 4.1x105 + 2071232.877(.4) = 1238493.151 m/s
Final Answer = 1238493.151
But the system says it's wrong...
Any help is appreciated! Thanks!