Calculate equivalent resistance

In summary: Current would flow from O to A and from A to N . Resistance between O and N would be 2r . Hence equivalent resistance is r/3
  • #1
Vibhor
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Homework Statement



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Homework Equations

The Attempt at a Solution



In the attached image the outer circular wire is represented as N . We have to find the equivalent resistance between O and N . Consider a battery of voltage V between O and N . From O there are six similar paths OA ,OB,OC,OD,OE,OF . Now , All six points would be equipotential . Consider any point , say A . No current would flow between A and B . From A there are three paths AX, AN,AY . AX and AY are symmetric w.r.t to AN so current would flow from A to X and then from X to N . Similarly current would flow from A to Y to N . Current would flow directly from A to N .I have drawn the currents in attached image .

Resistance between A and N would be 2r || r || 2r = r/2 .Resistance between O and N via A would be r+r/2 = 3r/2 . Now there are six similar parallel paths from O to N .Hence equivalent resistance would be r/4 .

Is that correct ? Is the reasoning also valid ?

Many Thanks
 

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  • #2
Vibhor said:

Homework Statement



View attachment 211076

Homework Equations

The Attempt at a Solution



In the attached image the outer circular wire is represented as N . We have to find the equivalent resistance between O and N . Consider a battery of voltage V between O and N . From O there are six similar paths OA ,OB,OC,OD,OE,OF . Now , All six points would be equipotential . Consider any point , say A . No current would flow between A and B . From A there are three paths AX, AN,AY . AX and AY are symmetric w.r.t to AN so current would flow from A to X and then from X to N . Similarly current would flow from A to Y to N . Current would flow directly from A to N .I have drawn the currents in attached image .

Resistance between A and N would be 2r || r || 2r = r/2 .Resistance between O and N via A would be r+r/2 = 3r/2 . Now there are six similar parallel paths from O to N .Hence equivalent resistance would be r/4 .

Is that correct ? Is the reasoning also valid ?

Many Thanks
That all looks right to me.
 
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  • #3
haruspex said:
That all looks right to me.

Thanks for confirming .

But official key states r/6 as the answer :eek: .
 
  • #4
Vibhor said:
Thanks for confirming .

But official key states r/6 as the answer :eek: .
That is clearly wrong. We could connect ABCDEF with a zero resistance, and the effective resistance from O to there would be r/6. There must be something to add to get to N.
 
  • #5
haruspex said:
That is clearly wrong. We could connect ABCDEF with a zero resistance, and the effective resistance from O to there would be r/6. There must be something to add to get to N.

Right .

Sorry , I had read answer of some other question in the key o:) .

Answer key states answer as r/3 .Solution says there would be no current in AX , XN , AY, YN wires . Current would flow from O to A and from A to N . Resistance between O and N would be 2r . Hence equivalent resistance is r/3 .
 
  • #6
Vibhor said:
Solution says there would be no current in AX , XN , AY, YN wires .
Again, clearly false.
 
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Related to Calculate equivalent resistance

What is equivalent resistance and why is it important?

Equivalent resistance is a measure of the total resistance of a circuit, which can be calculated by combining individual resistances in series or parallel. It is important because it helps determine the overall behavior of a circuit, such as the amount of current flowing through it and the amount of power dissipated.

How do you calculate equivalent resistance in a series circuit?

In a series circuit, the equivalent resistance is simply the sum of all individual resistances. This can be calculated using the formula Req = R1 + R2 + ... + Rn, where R1, R2, etc. are the individual resistances in the circuit.

How do you calculate equivalent resistance in a parallel circuit?

In a parallel circuit, the equivalent resistance is calculated differently depending on the number of resistances. If there are only two resistances, the formula is Req = (R1 * R2) / (R1 + R2). For more than two resistances, the formula is Req = 1 / ((1/R1) + (1/R2) + ... + (1/Rn)).

What is the difference between series and parallel circuits in terms of equivalent resistance?

In a series circuit, the equivalent resistance is always greater than any individual resistance, as the current has to flow through all resistances. In a parallel circuit, the equivalent resistance is always less than any individual resistance, as the current can split and flow through multiple paths.

How does temperature affect equivalent resistance?

As temperature increases, the resistance of most conductors also increases. This means that in a circuit with temperature-sensitive resistors, the equivalent resistance will also increase. This can affect the behavior of the circuit, such as decreasing the amount of current flowing through it.

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