Calculate Displacement Current from Electric Flux Density

In summary, the conversation discusses the calculation of displacement current density when given the electric flux density vector (xy, yz, xz). If the differentiation of electric flux density results in 0, it means that the field is electrostatic and not time varying. This can be seen in an example of a D.C voltage across a capacitor, where the current eventually becomes 0 due to the constant voltage. Therefore, in the absence of a time varying electric flux density, there will be no displacement current.
  • #1
JustStudying
27
0

Homework Statement


If electric flux density (D) is given by the vector (xy,yz,xz) then calculate the displacement current density


Homework Equations


Jd = dD/dt


The Attempt at a Solution


if you differentiate D, in terms of t, then you just get 0..but that apparently isn't the answer
 
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  • #2
If you are getting a "0" as differentiation of electric flux density that means that electric flux density is not changing with time,which means it is electrostatic and not time varying field. You can see this from an example, by keeping D.C voltage across capacitor the current in circuit becomes zero eventually this is because voltage is constant or of zero frequency. So if you don't have a time varying electric flux density there won't be displacement current.
 
  • #3
lazyaditya said:
If you are getting a "0" as differentiation of electric flux density that means that electric flux density is not changing with time,which means it is electrostatic and not time varying field. You can see this from an example, by keeping D.C voltage across capacitor the current in circuit becomes zero eventually this is because voltage is constant or of zero frequency. So if you don't have a time varying electric flux density there won't be displacement current.

This is what i think!
 

Related to Calculate Displacement Current from Electric Flux Density

1. What is displacement current?

Displacement current is a concept in electromagnetism that describes the flow of electric charge that is not carried by actual moving particles, but rather by the changing electric field itself.

2. How is displacement current related to electric flux density?

Displacement current is directly related to electric flux density, as it is the rate of change of electric flux density over time. This means that displacement current is a measure of the flow of electric flux through a given area.

3. How do you calculate displacement current?

Displacement current can be calculated using the equation ID= ε0 * dΦE/dt, where ID is the displacement current, ε0 is the permittivity of free space, and dΦE/dt is the rate of change of electric flux.

4. What are some real-world applications of calculating displacement current?

Displacement current is an important concept in the field of electromagnetism and has many real-world applications. It is used in the design of electronic circuits, antennas, and devices such as transformers and motors. It also plays a crucial role in understanding the behavior of electromagnetic waves.

5. How does displacement current differ from actual current?

Displacement current and actual current are both ways to measure the flow of electric charge, but they differ in how this charge is carried. Actual current is the movement of particles, such as electrons, while displacement current is the flow of electric charge through the changing electric field. Additionally, actual current can be measured with an ammeter, while displacement current is typically calculated using mathematical equations.

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