- #1
jwingeart
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Question:
You are cooking in a tent at 17,000ft with outside air temp at -15F. The concentration of CO in the tent is 40ppm. Calculate the equivalent CO concentration in mg/m^3.
First, I converted 17000ft to atm and got 501.5atm, which seems very wrong.
Next, I converted -15F to 247.039K.
I applied the Ideal Gas Law, PV=nRT
I tried to solve for V.
p=501.5 atm
n(molecular weight CO)=28
R (should be a constant)=.082056
T=247.039
I come up with a ridiculous answer. It seems simple, but I can't figure out where I'm going wrong.
You are cooking in a tent at 17,000ft with outside air temp at -15F. The concentration of CO in the tent is 40ppm. Calculate the equivalent CO concentration in mg/m^3.
First, I converted 17000ft to atm and got 501.5atm, which seems very wrong.
Next, I converted -15F to 247.039K.
I applied the Ideal Gas Law, PV=nRT
I tried to solve for V.
p=501.5 atm
n(molecular weight CO)=28
R (should be a constant)=.082056
T=247.039
I come up with a ridiculous answer. It seems simple, but I can't figure out where I'm going wrong.