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Hello all,

I haven't been on here for a while. I'm glad to see that everything is picking up nicely.

Anyway, I have a question that I see the answer to, but I am not understanding the concept.

Find the area of the region bounded by all leaves of the rose \(r=2\cos(3\theta)\)

The thing I am having a hard time grasping is the region of integration wrt \(\theta\). It appears that it is going from \(0\) to \(\pi\), but it seems to me that it should be \(0\) to \(2\pi\). However, that isn't correct.

Can anyone explain to me why the entire bottom half of the rose isn't included in the integration?

Thanks much,

Mac

I haven't been on here for a while. I'm glad to see that everything is picking up nicely.

Anyway, I have a question that I see the answer to, but I am not understanding the concept.

Find the area of the region bounded by all leaves of the rose \(r=2\cos(3\theta)\)

The thing I am having a hard time grasping is the region of integration wrt \(\theta\). It appears that it is going from \(0\) to \(\pi\), but it seems to me that it should be \(0\) to \(2\pi\). However, that isn't correct.

Can anyone explain to me why the entire bottom half of the rose isn't included in the integration?

Thanks much,

Mac

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