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- Jan 26, 2012

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Brie writes:

Hi everyone! I need a little help with finding a perpendicular line using an ordered pair and the equation to the previous line.

The equation is y= 3x+3 and the ordered pair is (1,1).

So far, I've used the slope-point equation to come up with such:

y-y1=m(x-x1)

y-1= -1/3(x-1)

y=(-1/3)(x)-(-1/3)(1)+1

At the end I ended up getting:

y=(-1/3)x+(1/3)+1

y=(-1/3)x+(4/3)

When I graph it, it's not going through the point (1,1) which it should. What am I doing wrong?

Thank you!

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