Box on Inclined Plane (with Friction)

In summary, a crate of mass 9.2 kg is pulled up a rough incline with an initial speed of 1.52 m/s using a force of 110 N at an angle of 20.6° with the horizontal. The coefficient of kinetic friction is 0.400 and the crate is pulled a distance of 4.94 m. To find the speed of the crate after being pulled 4.94 m, we use the equation W=(m*v(f)^2)/2 and solve for v(f) by taking the square root of (2W/m). However, this calculation does not take into account all the forces that do work, so the answer may be incorrect.
  • #1
B. variegatus
1
0

Homework Statement


A crate of mass 9.2 kg is pulled up a rough incline with an initial speed of 1.52 m/s. The pulling force is 110 N parallel to the incline, which makes an angle of 20.6° with the horizontal. The coefficient of kinetic friction is 0.400, and the crate is pulled 4.94 m.

(e) What is the speed of the crate after being pulled 4.94 m?

Homework Equations


F(f)=mu*N
E(k)=(mv^2)/2
U=mgh
delta E(k)= E(k1) - E(k2)
W=F*d
d=(a*t^2)/2

The Attempt at a Solution


W=(m*v(f)^2)/2
v(f)=sqrt(2W/m)
W=110*4.94=543.4J
v(f)=sqrt(543.4*2/9.2)=10.87ms^-1

The computer says that this is wrong though?
 
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  • #2
B. variegatus said:

Homework Statement


A crate of mass 9.2 kg is pulled up a rough incline with an initial speed of 1.52 m/s. The pulling force is 110 N parallel to the incline, which makes an angle of 20.6° with the horizontal. The coefficient of kinetic friction is 0.400, and the crate is pulled 4.94 m.

(e) What is the speed of the crate after being pulled 4.94 m?

Homework Equations


F(f)=mu*N
E(k)=(mv^2)/2
U=mgh
delta E(k)= E(k1) - E(k2)
W=F*d
d=(a*t^2)/2

The Attempt at a Solution


W=(m*v(f)^2)/2
v(f)=sqrt(2W/m)
W=110*4.94=543.4J
v(f)=sqrt(543.4*2/9.2)=10.87ms^-1

The computer says that this is wrong though?
total work is change in KE. You just gave the final,not the change. Also, more forces besides the applied force do work. You need to identify work done by all forces.
 

Related to Box on Inclined Plane (with Friction)

What is a box on an inclined plane with friction?

A box on an inclined plane with friction is a simple physics problem that involves a box placed on a sloped surface with some amount of friction acting upon it.

How is the acceleration of the box calculated?

The acceleration of the box is calculated using Newton's Second Law, which states that the net force acting on an object is equal to its mass multiplied by its acceleration. In this case, the net force is the force of gravity pulling the box down the slope minus the force of friction pushing against the box.

What factors affect the acceleration of the box?

The acceleration of the box is affected by the angle of the incline, the mass of the box, and the coefficient of friction between the box and the surface of the incline. A steeper incline, a heavier box, or a higher coefficient of friction will result in a slower acceleration.

How does friction affect the motion of the box?

Friction acts in the opposite direction of motion, so it will slow down the box as it moves down the incline. This is because friction converts some of the kinetic energy of the box into heat, decreasing its speed.

What is the purpose of this problem in physics?

The box on an inclined plane with friction problem serves as a practical application of Newton's Laws of Motion and allows for the calculation of various physical quantities, such as acceleration and net force. It also helps to demonstrate the effects of friction on an object's motion.

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