- #1
vysero
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Hello everyone. So I have a test coming up and I am struggling with the concept of figure out what the initial phase or angle of a transfer function is. For instance, consider the following transfer function:
L(s) = 4/s(.4s+1)(s+2)
So the initial angle for L(s) is -90 degrees. Is there a simple trick for figuring that out given any transfer function? I have heard that if there is a negative in the numerator then you add 180 degrees of phase or depending on the degree of the denominator you would subtract phase.
Can someone help me sort this out?
L(s) = 4/s(.4s+1)(s+2)
So the initial angle for L(s) is -90 degrees. Is there a simple trick for figuring that out given any transfer function? I have heard that if there is a negative in the numerator then you add 180 degrees of phase or depending on the degree of the denominator you would subtract phase.
Can someone help me sort this out?