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paulmdrdo
Active member
- May 13, 2013
- 386
find the term with $x^2$
$\displaystyle\left(x^2-\frac{1}{x}\right)^{10}$
thanks!
$\displaystyle\left(x^2-\frac{1}{x}\right)^{10}$
thanks!
Good, so what is the general term then, based on the binomial theorem?$\displaystyle a=x^2$ $\displaystyle b=\frac{1}{x}$
$k$ is the index of summation in the binomial theorem as I gave it above. Since $n=10$, there will be $11$ terms, for $k=0$ to $k=10$. $k=6$ represents the $7$th term.k should be 6. but still i'm kind of confused of what is that "k" stand for.