- #1
David VH
- 11
- 4
Here is what I want to know specifically: if I replace my 5cm wide rear tire with a 6.25cm wide tire, how much can I increase the inflation pressure to obtain the same comfort?
I realize "comfort" is not a quantifiable measurement, maybe shock absorption characteristics is better. Perhaps it can only be compared for one particular kind of shock? Representative for my use case would be riding over a +1cm step change in surface height at 10m/s. Wheel diameter is 723mm for the 5cm tire and 749mm for the 6cm tire.
Background facts that I am aware of:
- tire deforms so that load on the wheel equals contact patch area * inflation pressure (e.g. 15 cm^2 contact patch for 450N at 300 kPa),
- bumps cause the tire to widen locally so that the outer edge moves inwards while preserving volume.
Any ideas? Remarks?
I realize "comfort" is not a quantifiable measurement, maybe shock absorption characteristics is better. Perhaps it can only be compared for one particular kind of shock? Representative for my use case would be riding over a +1cm step change in surface height at 10m/s. Wheel diameter is 723mm for the 5cm tire and 749mm for the 6cm tire.
Background facts that I am aware of:
- tire deforms so that load on the wheel equals contact patch area * inflation pressure (e.g. 15 cm^2 contact patch for 450N at 300 kPa),
- bumps cause the tire to widen locally so that the outer edge moves inwards while preserving volume.
Any ideas? Remarks?