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Homework Statement
C14 disintegrates by b-emission with a reaction
energy (q value) of 0.155 MeV. A b-particles with an
energy of 0.025MeV is emitted in a direction at 135°
to the direction of motion of the recoil nucleus. Then
the momenta of the three particles (b = V, 14N)
involved in this disintegration in MeV/c units will
be. (where, c is speed of light in vacuum) (M0 = 0.511
MeV/c2 )
Homework Equations
Q=Total Energy. therefore Q= 0.025+ energy of nitrogen atom + antineutrino
The Attempt at a Solution
Q=P^2/2m(nitrogen) +p^2/2m(beta particle)