Behaviour of intrinsic semiconductor to an electric field

The depletion region in an intrinsic semiconductor junction can be formed by the application of an electric field in forward bias. However, since the intrinsic region has no dopants, it can also be formed by the adjoining of a doped region. This depletion region can be created without any p-n junctions. Additionally, the intrinsic region, which is typically pure Si, can still have free carriers due to thermal generation of electron-hole pairs. This information helps to explain how a depletion region can be formed in an intrinsic semiconductor junction and that it can leave behind negative or positive ions. In summary, the formation of a depletion region in intrinsic Si can occur through an applied electric field or by adjoining a doped region, and can result in the presence of
  • #1
arunkumarcea
2
0
If I have a semiconductor junction of p-i and an electric field applied to it in forward bias, will the current flow?. How is the depletion region formed in intrinsic region since there are no free carriers there.What will be the electric field distribution through the intrinsic region?
 
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  • #2
What makes you believe there are no free carriers in intrinsic Si? Intrinsic Si has not been doped with any acceptor or donor elements, ideally it is pure Si. Electron-hole pairs are being thermally generated constantly just like with n and p type Si. The i layer has free carriers, except of course in a depletion zone. Did this help?

Claude
 
  • #3
How can a depletion region be formed in intrinsic Si?Will they leave behind negative ions or positive ions?
 
  • #4
arunkumarcea said:
How can a depletion region be formed in intrinsic Si?Will they leave behind negative ions or positive ions?

When an intrinsic region adjoins a doped region, there can be depletion. If a slab of intrinsic is energized w/o any p-n junctions then there is no depletion.

Claude
 
  • #5


I can provide an explanation for the behavior of intrinsic semiconductors in the presence of an electric field. In an intrinsic semiconductor, the number of electrons and holes is equal, resulting in a balance between the two charge carriers. When an electric field is applied to the semiconductor junction in forward bias, the majority carriers (either electrons or holes) will experience a force in the direction of the electric field and will start to move towards the opposite side of the junction. This movement of charge carriers will result in a flow of current through the semiconductor.

The depletion region in the intrinsic region is formed due to the diffusion of charge carriers from the p and n regions towards the junction. In an intrinsic semiconductor, there are no impurities or dopants present to create free carriers. However, there are still some thermally generated electron-hole pairs present in the intrinsic region. When an electric field is applied, these electron-hole pairs will be separated and contribute to the formation of the depletion region.

The electric field distribution through the intrinsic region will depend on the doping concentration and the applied voltage. In a highly doped semiconductor, the electric field will be mostly concentrated near the junction due to the high concentration of charge carriers. In a lightly doped semiconductor, the electric field will be more evenly distributed throughout the intrinsic region. However, in both cases, the electric field will be strongest near the junction and will decrease as we move away from it.

In summary, the behavior of intrinsic semiconductors to an electric field is characterized by the movement of charge carriers and the formation of a depletion region. The electric field distribution through the intrinsic region will depend on the doping concentration and applied voltage.
 

Related to Behaviour of intrinsic semiconductor to an electric field

What is an intrinsic semiconductor?

An intrinsic semiconductor is a material that has equal numbers of positive and negative charge carriers, making it electrically neutral. This means that it does not have any impurities added to it to change its electrical properties.

How does an electric field affect an intrinsic semiconductor?

An electric field can cause the electrons in an intrinsic semiconductor to move towards the positive terminal and the holes (absence of electrons) to move towards the negative terminal. This creates a current flow in the material.

What happens to the band gap of an intrinsic semiconductor in an electric field?

The band gap of an intrinsic semiconductor increases as the electric field increases. This means that it becomes harder for electrons to jump from the valence band to the conduction band, resulting in a decrease in conductivity.

How does the mobility of charge carriers in an intrinsic semiconductor change with an electric field?

The mobility of charge carriers in an intrinsic semiconductor increases with an increase in electric field. This is because the electric field provides a force that helps the charge carriers move more easily through the material.

Can an intrinsic semiconductor become a conductor under an electric field?

Yes, an intrinsic semiconductor can become a conductor under an electric field. However, this typically requires a very strong electric field as the band gap of an intrinsic semiconductor is relatively large compared to doped semiconductors.

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