Be+ vs B+ Ionic Radii: Proton-Electron Ratio Analysis

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This leads to a stronger attraction between the protons and electrons in Be+, resulting in a smaller ionic radius. In summary, Be+ has a smaller ionic radius compared to B+ due to the higher proton-electron ratio and stronger attraction between the particles in the ion.
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MathewsMD
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When competing the ionic radii of Be+ and B+, which is smaller? I understand there are periodic trends but there is an anomaly in ionization energies b/w B and Be since B has a lone 2p electron. So instead of looking at periodic trends directly, I assessed the proton-electron ratio and found for these cations, Be has a higher ratio (4/3 vs 5/4). This led me to believe Be+ has a smaller ionic radius compared to B+ since there is a stronger general attraction b/w the protons and electrons in this ion.

Any clarifications and comments on my thought process would be greatly appreciated!
 
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Your thought process is correct. Beryllium (Be+) has a smaller ionic radius than Boron (B+), due to the higher proton-electron ratio in Be+. This anomaly in ionization energies between B and Be is due to the fact that B has a lone 2p electron, which is more difficult to remove than the 2s electron in Be.
 

Related to Be+ vs B+ Ionic Radii: Proton-Electron Ratio Analysis

1. What is the difference between Be+ and B+ ions in terms of their ionic radii?

Be+ and B+ ions are both positively charged ions, but they differ in the number of electrons they have. Be+ ions have one less electron than B+ ions, resulting in a smaller ionic radius for Be+. This is because the positive charge of the nucleus in Be+ is able to pull the remaining electrons closer, making the ion more compact.

2. How does the proton-electron ratio affect the ionic radii of Be+ and B+ ions?

The proton-electron ratio is an important factor in determining the ionic radii of Be+ and B+ ions. As the number of protons increases in an ion, the positive charge of the nucleus becomes stronger and is able to pull the electrons closer, resulting in a smaller ionic radius. Therefore, since Be+ has a higher proton-electron ratio than B+, it has a smaller ionic radius.

3. Why does the ionization of Be and B result in the formation of Be+ and B+ ions?

Be and B are both elements in the second group of the periodic table, which means they have two valence electrons. In order to achieve a stable octet configuration, they must either lose these two electrons to form a positive ion or gain six electrons to form a negative ion. Since it requires less energy for Be and B to lose two electrons, they are more likely to form Be+ and B+ ions rather than gain six electrons.

4. How do the ionic radii of Be+ and B+ compare to their atomic radii?

The ionic radii of Be+ and B+ are significantly smaller than their atomic radii. This is because when an atom loses electrons to form an ion, the positive charge of the nucleus becomes stronger and is able to pull the remaining electrons closer. This results in a decrease in the ionic radius compared to the atomic radius.

5. What are the practical applications of understanding the differences in ionic radii between Be+ and B+ ions?

Understanding the differences in ionic radii between Be+ and B+ ions is important in various fields such as materials science and chemistry. For example, it can help in the design and synthesis of new materials, as well as in predicting the reactivity and properties of different compounds. Additionally, this knowledge can also be applied in the field of medicine, particularly in drug development and delivery.

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