# [SOLVED]Basic question on selection numbers

#### karush

##### Well-known member
 1.1 Among the digits 1,2,3,4,5 first one is chosen, and then a second selection is made among the remaining four digits. Assume that all twenty possible results have the same probability. Find the probability that an odd digit will be selected. $\frac{3}{5}$ The second time $\frac{3}{5}$ The third time $\frac{3}{10}$
my question on this was how do they get 20 possible results on if one odd is taken away after the selection, and did not understand how $\frac{3}{10}$ was derived? thanks ahead....

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