Dec 9, 2020 Thread starter #1 S solakis Active member Dec 9, 2012 352 Prove: $A\leq B\wedge B\leq A\Rightarrow A=B$
Dec 9, 2020 #2 C Country Boy Well-known member MHB Math Helper Jan 30, 2018 580 Trichotomy: Given numbers A and B, one and only one must be true: 1) A> B 2) A< B 3) A= B Since \(\displaystyle A\le B\), A> B is not true. Since \(\displaystyle B\le A\), A< B is not true.
Trichotomy: Given numbers A and B, one and only one must be true: 1) A> B 2) A< B 3) A= B Since \(\displaystyle A\le B\), A> B is not true. Since \(\displaystyle B\le A\), A< B is not true.
Dec 9, 2020 Thread starter #3 S solakis Active member Dec 9, 2012 352 Is the trichotomy law you are using Equivelant to the following: $A<B\vee B<A\vee A=B$
