That's correct. (I see you modeled the barrel as a solid cylinder, which is OK.)dislect said:For rolling without slip:
mgh=0.5Iω + 0.5mV^2, I=0.5MR^2 ->
mgh=0.25mR^2 * (V/R)^2 +0.5MV^2
gh=0.25V^2 + 0.5V^2 ->
V=√4/3 gh
For slip only:
mgh=0.5mV^2 ->
V=√2gh
and so the Velocity at the bottom of the inclined plane is higher for slip only. is that correct?
A barrel roll is a type of aerial maneuver in which an aircraft rotates 360 degrees along its longitudinal axis while maintaining its altitude and direction of travel.
A barrel roll without slipping refers to a perfectly coordinated maneuver where the aircraft's nose stays on the same flight path throughout the roll. A barrel roll with slipping, on the other hand, involves the aircraft slipping or sliding off its original flight path during the roll.
An aircraft can slip during a barrel roll due to uneven lift distribution, uncoordinated control inputs, or external factors such as wind or turbulence. This can result in a loss of altitude and deviation from the intended flight path.
When performed correctly, a barrel roll is a safe and controlled maneuver. However, it should only be attempted by trained and experienced pilots in appropriate aircraft and conditions. Improper execution or attempting a barrel roll in unsuitable conditions can lead to loss of control and potential accidents.
Barrel rolls are primarily used in aerobatic displays to showcase the agility and capabilities of an aircraft. They can also be used in certain situations to evade enemy attacks or as a defensive maneuver in combat. However, they are not typically used in day-to-day flight operations.