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- Thread starter SDAlgebra
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- Jan 30, 2012

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- Jan 30, 2018

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"The ratio of counters in box A to box B is 5:3."

so a/5= b/3 and 3a= 5b

"The ratio of counters in box B to box C is 2:1."

so b/2= c/1 and b= 2c.

"Some counters are removed from box A."

Call the number of counters removed x. Now there are a- x counters in box A.

"54 counters are moved from box B to box C."

Now there are b- 54 counters in box B and c+ 54 counters in box C.

"There are now the same number of counters in each box."

a- x= b- 54 and b- 54= c+ 54.

We have four equations

3a= 5b

b= 2c

a- x= b- 54 and

b- 54= c+ 54

to solve for a, b, c, and x.