Balloon problem, thermodynamics

In summary, a helium balloon is used to lift a load of 110 N, with the weight of the balloon's skin being 50 N. The volume of the balloon when fully inflated is 32 m3 and the temperature of the air is 0°C with an atmospheric pressure of 1 atm. The balloon is filled with enough helium gas to produce a net buoyant force of 30 N. The number of moles of helium gas contained in the balloon can be calculated using the equation FB = mg + 30 N. By knowing the density of air and helium gas, the net upward force can be calculated as (buoyant force) - (weights), resulting in a value of V = 17.38 m3.
  • #1
illidari
47
0

Homework Statement



A helium balloon is used to lift a load of 110 N. The weight of the balloon's skin is 50 N, and the volume of the balloon when fully inflated is 32 m3. The temperature of the air is 0°C and the atmospheric pressure is 1 atm. The balloon is inflated with sufficient helium gas so that the net buoyant force on the balloon and its load is
30 N. Neglect changes of temperature with altitude.

(a) How many moles of helium gas are contained in the balloon?




Homework Equations



Find V from FB = mg + 30 N
PairVg = 190 N + PHeVg; V = 17.38 m3

The Attempt at a Solution



I am confused on how you get the V=17.38 from using the equation I posted. Could someone explain that part to me.
 
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  • #2
First, let me just say that the question is being a bit sloppy in using "net buoyant force" to mean the net upward force (the sum of all contributions in the vertical direction -- which includes the buoyant force due to the air displaced by helium gas).

Moving on...

The helium gas displaces an equal volume of air, thus producing lift (buoyant force). You'll need to look up the density of air and the density of helium gas (you can calculate the latter from the molar mass of helium and the molar volume of a gas at 0 degrees and 1 atmosphere pressure).

The net upward force is then (buoyant force) - weights
 
  • #3
Didn't realize these were just stuff I had to look up...

Density air = 1.293
density helium = .1786

190/ (1.293-.1786 * 9.81) = 17.38

>.< Well an answer is an answer

Thanks!
 

Related to Balloon problem, thermodynamics

1. What is the balloon problem in thermodynamics?

The balloon problem in thermodynamics refers to the behavior of a gas-filled balloon when it is exposed to changes in temperature and pressure. This problem is often used to illustrate the principles of ideal gas laws and how they apply to real-world situations.

2. How does the temperature affect the size of a balloon?

According to the ideal gas law, an increase in temperature will cause the gas molecules inside the balloon to move faster and collide with the walls of the balloon more frequently, increasing the pressure inside and causing the balloon to expand.

3. What happens to the pressure inside a balloon when it is heated?

When a balloon is heated, the gas molecules inside gain kinetic energy and move faster, increasing the pressure inside. This is because the molecules are colliding with the walls of the balloon more frequently and with greater force.

4. Why does a balloon deflate when it is placed in the freezer?

When a balloon is placed in the freezer, the temperature decreases and the gas molecules inside slow down, resulting in a decrease in pressure. This decrease in pressure causes the balloon to deflate as the gas molecules are not colliding with the walls of the balloon as frequently.

5. What is the relationship between the volume and pressure of a balloon?

The volume and pressure of a balloon have an inverse relationship, meaning that as one increases, the other decreases. This is described by Boyle's Law, which states that at a constant temperature, the volume of a gas is inversely proportional to its pressure.

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