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okh
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Homework Statement
A 900 kg car goes up along an inclined road by 30 degrees characterized by an acceleration of 0.25 m/s^2. If friction coefficient is 0.5, find the magnitude of the force that moves the car.
Solution: F = 12285.6 N
Homework Equations
The Attempt at a Solution
http://img259.imageshack.us/img259/5361/imagetcq.jpg
Sum of all forces is: m *a = 900 * 0.25 = 225
Then Ffriction is = 0.5 * FwPerpendicular = 0.5 * sin(60) * 900 * 9.8 = 3819 N
Then Fwparallel is = sin(60) * 900 * 9.8 = 4410
F = 3819 + 4410 + 225 = 8454 N != solution
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