Welcome to our community

Be a part of something great, join today!

Average value

nghijen

New member
Jul 7, 2020
2
I have attempted to solve the question but I still do not understand. Can someone please help me?
IMG_5255.jpeg
 

skeeter

Well-known member
MHB Math Helper
Mar 1, 2012
655
average value of a function involves a definite integral over an interval ... from your shading, is the given interval $[0,u]$ ?
 

nghijen

New member
Jul 7, 2020
2
average value of a function involves a definite integral over an interval ... from your shading, is the given interval $[0,u]$ ?
I am assuming it is [0, u] !
 

skeeter

Well-known member
MHB Math Helper
Mar 1, 2012
655

Country Boy

Well-known member
MHB Math Helper
Jan 30, 2018
426
I frankly can't understand what you think you are doing! Much of what you are doing is determining where f(x)= 0. Okay that is at x= 5, which you have, and x= 0, which you ignore, but that is irrelevant anyway! The average value of a function, f(x), over interval a to b is the integral of f, from a to b, divided by b- a. But you show no attempt at integration!