- #1
frizzler43
- 2
- 0
A person walks first at a constant speed of 5.01 m/x along a straight line from point A to B and then back along the line from B to A at a constant speed of 3.10 m/s
What is the average speed over the entire trip?
I've tried everything from adding the two and dividing by two. I've found that the avg. velocity over the trip is 0 m/s.
I know that avg speed=distance over time. I just don't know how you are suppose to find the time o if that's even what you're suppose to do
What is the average speed over the entire trip?
I've tried everything from adding the two and dividing by two. I've found that the avg. velocity over the trip is 0 m/s.
I know that avg speed=distance over time. I just don't know how you are suppose to find the time o if that's even what you're suppose to do