Mar17 said:Homework Statement
what is the average power output of an engine lifts a 250kg mass a distance of 30.0m in 20.0s?
Homework Equations
Ek= (1/2)(m)(v^2)
Ep=mgh
Ew=fnet x distance
Es= (1/2)kx^2
The Attempt at a Solution
Ep+Ek=f x d
(.5)(200)(3)^2 + (200)(9.81)(5)= fx5.00
900+9810/5.00=f
f=2142N
The average power output of a machine is the amount of work performed by the machine over a given time period, divided by the duration of that time period.
Average power output is calculated by dividing the work output of a machine by the time it takes to perform that work. This is expressed as the formula P = W/t, where P represents power, W represents work, and t represents time.
Average power output is the average amount of work performed by a machine over a period of time, while maximum power output is the highest amount of work that the machine is capable of performing in a single instant.
Average power output is directly related to the efficiency of a machine. A higher average power output indicates that the machine is able to perform work more quickly and efficiently, while a lower average power output may indicate inefficiency or limitations in the machine's design.
Average power output can be increased by improving the design and function of a machine, such as reducing friction and increasing the efficiency of energy conversion. Additionally, using higher quality materials and maintaining the machine properly can also help to increase its average power output.