Average force in stopping a block

In summary, a 300kg block is suspended by a cable. When the cable snaps, the block falls 3 metres to the ground below. The time taken for the block to reach the ground is 0.78 seconds and the impact velocity of the block with the ground is 7.65m/s down. The average force exerted by the ground in stopping the block is 882900N.
  • #1
ride4life
33
0

Homework Statement


A 300kg block is suspended by a cable.
a) what is the weight of the motor block?
b) the cable snaps and the block falls 3 metres to the ground below.
i) calculate the time taken for the block to reach the ground.
ii) calculate the impact velocity of the block with the ground
c) if the block comes to rest having caused a 1cm dent in the block (ie traveled 1cm in coming to rest), calculate the average force exerted by the ground in stopping the block.

Homework Equations


a) weight = mass x gravity
b) i) s = ut + 0.5at^2
ii) v = u + at
c) ?


The Attempt at a Solution


a) weight = 300x9.81 = 2943N down
b) i) 3 = 0.5 x 9.81 x t^2 t = 0.78s
ii) v = 9.81 x 0.78 = 7.65m/s down
c) no idea
 
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  • #2
Work done against the block = change in gravitational potential energy of the block.
(Conservation of energy)
 
  • #3
work done = potential energy
w = m.g.h
w = 300x9.81x3
w = 8829 joules

is that right?
 
  • #4
ride4life said:
work done = potential energy
w = m.g.h
w = 300x9.81x3
w = 8829 joules

is that right?

Right, so if you have the work done on the block. How would you find the force if you are given the distance?
 
  • #5
work = force x displacement

foce = 8829/3

force = 2943N
 
  • #6
ride4life said:
work = force x displacement

foce = 8829/3

force = 2943N

The block travels 1cm before coming to rest.
 
  • #7
2943 x 0.01?
 
  • #8
ride4life said:
2943 x 0.01?

the unit of 2943 x 0.01 is not Newton (the question is about force)

rock.freak667 talked about what the force is if the block traveled 1 cm with some amount of work done.
 
  • #9
so it's 2943x0.01 J?
 
  • #10
ride4life said:
calculate the average force exerted by the ground in stopping the block.

What is the unit of force?
 
  • #11
songoku said:
What is the unit of force?

Newtons
 
  • #12
ride4life said:
2943 x 0.01?

will the unit of this calculation be Newton?
 
  • #13
songoku said:
will the unit of this calculation be Newton?

Newton seconds?
 
  • #14
lol

yes it's Newton seconds and that's unit of momentum, not force.
Since the question is about force, no doubt the answer is wrong.

you have the distance and work, find F
 
  • #15
s = 0.01m
W = 300x9.81x3
F = W/s
F = 882900N
 
  • #16
Looks good.

I recommend getting in the habit of including units during your calculations, and not just sticking them on at the end. Including units should help you understand better what's going on, and will help you catch errors like thinking that "2943 x 0.01" represents a force.
 
  • #17
Redbelly98 said:
Looks good.

I recommend getting in the habit of including units during your calculations, and not just sticking them on at the end. Including units should help you understand better what's going on, and will help you catch errors like thinking that "2943 x 0.01" represents a force.

Ok, thanks for the advice! :biggrin:
 

Related to Average force in stopping a block

1. What is average force in stopping a block?

The average force in stopping a block refers to the amount of force that is exerted on a moving block to bring it to a complete stop within a certain distance. This force is typically measured in Newtons (N) and is calculated by dividing the change in momentum of the block by the time it takes to stop.

2. How is average force in stopping a block calculated?

The average force in stopping a block is calculated by dividing the change in momentum (mass x velocity) of the block by the time it takes to stop. The formula is F = Δp / Δt, where F is the average force, Δp is the change in momentum, and Δt is the time it takes to stop.

3. What factors affect the average force in stopping a block?

The average force in stopping a block is affected by several factors such as the mass of the block, the initial velocity of the block, and the distance over which the block needs to be stopped. Additionally, external factors such as friction and air resistance can also impact the average force.

4. How does the average force in stopping a block relate to Newton's laws of motion?

The average force in stopping a block is a direct application of Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration. In this case, the acceleration is the change in velocity over time, and the net force is the average force needed to bring the block to a complete stop.

5. Why is it important to calculate the average force in stopping a block?

Calculating the average force in stopping a block is important for understanding and analyzing the motion of objects. It can help engineers design safer and more efficient braking systems, and it can also provide valuable information for predicting and preventing collisions in various scenarios. Additionally, understanding the average force in stopping a block is crucial for ensuring the safety of individuals and equipment in a variety of situations, such as during car accidents or in industrial settings.

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