Average force in baseball help?

[seanbugler]

Homework Statement

A 0.140-kg baseball traveling 33.0 m/s strikes the catcher's mitt, which, in bringing the ball to rest, recoils backward 13.0 cm.
What was the average force applied by the ball on the glove?

Homework Equations

F=[tex]\Delta[/tex]M/[tex]\Delta[/tex]T

The Attempt at a Solution

I don't know how to find the data to plug into the equation.

 

[rl.bhat]

Homework Statement

A 0.140-kg baseball traveling 33.0 m/s strikes the catcher's mitt, which, in bringing the ball to rest, recoils backward 13.0 cm.
What was the average force applied by the ball on the glove?

Homework Equations

F=[tex]\Delta[/tex]M/[tex]\Delta[/tex]T

The Attempt at a Solution

I don't know how to find the data to plug into the equation.

Initial velocity is given, final velocity is zero. Displacement is given. find the acceleration.

 

[tomcue]

I would first gather all the necessary information to solve this problem. This includes the mass of the baseball (0.140 kg), its initial velocity (33.0 m/s), and the distance the catcher's mitt recoiled (13.0 cm).

Next, I would use the equation F = mΔv/Δt to calculate the average force applied by the ball on the glove. Since the ball was brought to rest, its final velocity is 0 m/s, and the time it took for the ball to come to a stop can be calculated using the distance and initial velocity. Plugging in all the values, we get:

F = (0.140 kg)(0 - 33.0 m/s)/ (Δt)

Using d = v0t + 1/2at^2, we can solve for Δt:

0.13 m = (33.0 m/s)(Δt) + 1/2(-9.8 m/s^2)(Δt)^2

Solving for Δt, we get Δt = 0.02 s.

Plugging this back into the original equation, we get:

F = (0.140 kg)(0 - 33.0 m/s)/ (0.02 s) = 2.31 N

Therefore, the average force applied by the ball on the glove is 2.31 N. This means that the glove experienced a force of 2.31 Newtons while bringing the ball to a stop. This information can be useful for understanding the impact of the ball on the catcher's hand and the strength required to catch it.