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#### karush

##### Well-known member

- Jan 31, 2012

- 3,187

IB24

1202

2000

(a) $E\cup H = 88-39=49$ and since $32+28=60$ then $b=60-49= E\cap H = 11$

so $a=32-11=21$ and $c=28-11=17$

hope this ok before (b) and (c)

1202

2000

(a) $E\cup H = 88-39=49$ and since $32+28=60$ then $b=60-49= E\cap H = 11$

so $a=32-11=21$ and $c=28-11=17$

hope this ok before (b) and (c)

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