- #1
apunisheriii
If a photon of wavelength 663nm is incident on a hydrogen atom in its fourth excited state(n=5),then
A.the atom doesn't absorb the photon
B.the atom absorbs the photon but is not ionized
C.the atom absorbs the photon and is ionized,with the electron having zero kinetic energy after ionization
D.the atom absorbs the photon and is ionized,with the electron having kinetic energy 1.33eV after ionization.
the answer is D
but i couldn't approach tat answer when I am using 1/lambda=R(1/n1-1/n22)
after sub in the values into this equation
whole thing seems to be wrong...as 1/25-1/25=0
how can i know tat the photon with wavelength 663nm is able to ionize the atom??
and how to find the electron's kinetic energy after ionization?
A.the atom doesn't absorb the photon
B.the atom absorbs the photon but is not ionized
C.the atom absorbs the photon and is ionized,with the electron having zero kinetic energy after ionization
D.the atom absorbs the photon and is ionized,with the electron having kinetic energy 1.33eV after ionization.
the answer is D
but i couldn't approach tat answer when I am using 1/lambda=R(1/n1-1/n22)
after sub in the values into this equation
whole thing seems to be wrong...as 1/25-1/25=0
how can i know tat the photon with wavelength 663nm is able to ionize the atom??
and how to find the electron's kinetic energy after ionization?