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#### Monoxdifly

##### Well-known member

- Aug 6, 2015

- 284

I substituted all known variables (including the gravity acceleration \(\displaystyle 10m/s^2\), with \(\displaystyle \sin37^{\circ}=\frac{3}{5}\) and \(\displaystyle \cos37^{\circ}=\frac{4}{5}\)) to \(\displaystyle x=v_0\cos\alpha t\) and \(\displaystyle y=v_0\sin\alpha t-\frac{1}{2}gt^2\). Substituting the \(\displaystyle v_0\) I got from both equations resulted in \(\displaystyle \frac{125}{2t}=\frac{40+25t^2}{3t}\) and I got \(\displaystyle t^2=5,9\). Am I right? Because if it is indeed the right value of t, everything will be complicated from there.