- #1
Major Mei
- 4
- 0
Hello guys,
I tried to figure this out and I got my answer. I just want to check it. So would you guys please help me with it? Thank you!
Here is the question:
A nonconducting rod of length 2a has a charge Q uniformly distributed along it. Find the expression for x-component of the electric field at point P(a distance above one of the ends of the rod)
my answer:
Ex = Integral from x = -2a to 0 of [(k*Q/2a)*xdx/ (x^2+a^2)^(3/s2)]
set x^2+a^2 = y
x*dx = dy/2 also x = -2a y = 5a^2
x = 0 y =a^2
Ex = -2*(k*Q/4a)[1/sq rt(y)] within limits of y = 5a^2 to y = a^2]
= - (kQ/2a)*[1/sq rt(5a^2) – 1/sq rt(a^2)] = -(kQ/2a^2)[1/sq rt(5) -1]
= [kQ/(2a^2*sq rt(5))]*{sq rt(5) -1]
is that correct?
Thank you and I am willing to learn from you ;)
I tried to figure this out and I got my answer. I just want to check it. So would you guys please help me with it? Thank you!
Here is the question:
A nonconducting rod of length 2a has a charge Q uniformly distributed along it. Find the expression for x-component of the electric field at point P(a distance above one of the ends of the rod)
my answer:
Ex = Integral from x = -2a to 0 of [(k*Q/2a)*xdx/ (x^2+a^2)^(3/s2)]
set x^2+a^2 = y
x*dx = dy/2 also x = -2a y = 5a^2
x = 0 y =a^2
Ex = -2*(k*Q/4a)[1/sq rt(y)] within limits of y = 5a^2 to y = a^2]
= - (kQ/2a)*[1/sq rt(5a^2) – 1/sq rt(a^2)] = -(kQ/2a^2)[1/sq rt(5) -1]
= [kQ/(2a^2*sq rt(5))]*{sq rt(5) -1]
is that correct?
Thank you and I am willing to learn from you ;)