Art of Electronics Exercise 4.3 Operational inverter

In summary, the circuits in Figure 4.14 let you invert or amplify without inversion, by flipping a switch. The voltage gain is either +1 or -1, depending on the switch position.
  • #1
CSOleson
17
0

Homework Statement


The circuits in Figure 4.14 let you invert or amplify without inversion, by flipping a switch. The voltage gain is either +1 or -1, depending on the switch position.
http://tinypic.com/r/2hnql2c/6
http://tinypic.com/r/2hnql2c/6

Homework Equations


Gain for the first image with the switch set to ground is equal to -R2/R1, because it is an inverting amplifier, struggling to identify how to consider the circuit as a follower, because it doesn't look like a typical follower circuit. Unsure how to consider the circuit when the positive and negative terminals are connected.


The Attempt at a Solution

 
Last edited:
Physics news on Phys.org
  • #2
CSOleson said:

Homework Statement


The circuits in Figure 4.14 let you invert or amplify without inversion, by flipping a switch. The voltage gain is either +1 or -1, depending on the switch position.
http://tinypic.com/r/2hnql2c/6
http://tinypic.com/r/2hnql2c/6

Homework Equations


Gain for the first image with the switch set to ground is equal to -R2/R1, because it is an inverting amplifier, struggling to identify how to consider the circuit as a follower, because it doesn't look like a typical follower circuit. Unsure how to consider the circuit when the positive and negative terminals are connected.


The Attempt at a Solution


What is the difference in voltage between the + and - inputs for an opamp in the follower configuration? So what is the feedback current in this configuration? :smile:
 
  • #3
are the + and - inputs equal, because of the negative feedback loop?
 
  • #4
so the voltage across the 1st resistor would be 0V because it is V+ - V-
 
  • #5
CSOleson said:
are the + and - inputs equal, because of the negative feedback loop?

CSOleson said:
so the voltage across the 1st resistor would be 0V because it is V+ - V-

Correct-a-mundo :smile:

Kind of a weird follower, but that's one of the ways that H&H teaches us how to be comfortable thinking about circuits. Have you seen this thread?

https://www.physicsforums.com/newreply.php?do=newreply&p=4315656

:smile:
 
Last edited by a moderator:

Related to Art of Electronics Exercise 4.3 Operational inverter

1. What is an operational inverter?

An operational inverter is a type of electronic circuit that takes an input voltage and produces an output voltage that is the opposite polarity. It is typically used to convert a positive voltage to a negative voltage or vice versa.

2. How does an operational inverter work?

An operational inverter consists of two complementary transistors, one NPN and one PNP, connected in a push-pull configuration. When the input voltage is high, the NPN transistor is turned on and the PNP transistor is turned off, allowing current to flow through the circuit. This produces a low output voltage. When the input voltage is low, the NPN transistor is turned off and the PNP transistor is turned on, allowing current to flow in the opposite direction and producing a high output voltage.

3. What is the purpose of Exercise 4.3 in "Art of Electronics"?

Exercise 4.3 in "Art of Electronics" is designed to teach readers how to design and build an operational inverter circuit using basic electronic components. It also helps readers understand the principles behind how an operational inverter works and how it can be used in practical applications.

4. What are some common applications of operational inverters?

Operational inverters are commonly used in power supplies, signal amplifiers, and other electronic circuits that require a negative voltage source. They can also be used in logic gates and other digital circuits to invert or reverse the logic of a signal.

5. Are there any limitations or considerations when using operational inverters?

One limitation of operational inverters is that they can only handle a certain range of input voltages and output currents. It is important to carefully select the appropriate components and values for the circuit to ensure it can handle the desired inputs and outputs. Additionally, operational inverters can introduce some noise and distortion to the output signal, so they may not be suitable for high precision applications.

Similar threads

  • Engineering and Comp Sci Homework Help
Replies
4
Views
2K
  • Engineering and Comp Sci Homework Help
Replies
1
Views
410
  • Engineering and Comp Sci Homework Help
Replies
3
Views
2K
  • Engineering and Comp Sci Homework Help
Replies
3
Views
1K
Replies
33
Views
4K
  • Engineering and Comp Sci Homework Help
Replies
5
Views
4K
Replies
5
Views
2K
  • Engineering and Comp Sci Homework Help
Replies
4
Views
2K
  • Engineering and Comp Sci Homework Help
Replies
5
Views
2K
  • Introductory Physics Homework Help
Replies
10
Views
1K
Back
Top