- #1
endangered
- 4
- 0
Hey,
(sin A + sin B + sin C)/3 >= [tex]\sqrt[3]{}[/tex](sin A*sin B*sin C)
I know this is true by Arithmetic mean always greater than geometric mean...
but is there any other way of proving this?
(sin A + sin B + sin C)/3 >= [tex]\sqrt[3]{}[/tex](sin A*sin B*sin C)
I know this is true by Arithmetic mean always greater than geometric mean...
but is there any other way of proving this?