Arithmetic mean always greater than geometric mean

In summary, the arithmetic mean is always greater than the geometric mean because it takes into account the magnitude of each value in a set. However, in cases where all the numbers in the set are the same, the two means can be equal. The significance of the arithmetic mean being greater than the geometric mean is that it indicates uneven distribution of values and can help identify outliers. However, the arithmetic mean may not always accurately represent the central tendency of a data set, especially when there are extreme outliers. In certain distributions, such as bimodal distributions, the arithmetic mean may also not be greater than the geometric mean.
  • #1
endangered
4
0
Hey,

(sin A + sin B + sin C)/3 >= [tex]\sqrt[3]{}[/tex](sin A*sin B*sin C)

I know this is true by Arithmetic mean always greater than geometric mean...
but is there any other way of proving this?
 
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  • #2
What about something along the lines of:

[tex]\left[ \frac13 (\sin A + \sin B + \sin C) \right]^3 \ge \frac19 \left( \sin^3 A + \sin^3 B + \sin^3 C \right) \ge \frac13 \sin^3 A \ge \sin A \sin B \sin C[/tex]
 

Related to Arithmetic mean always greater than geometric mean

1. Why is the arithmetic mean always greater than the geometric mean?

The arithmetic mean is calculated by adding all the numbers in a set and dividing by the number of values. This results in a larger number than the geometric mean, which is calculated by taking the nth root of the product of all the numbers in the set. Since the arithmetic mean takes into account the magnitude of each value, it is always greater than the geometric mean, which only considers their relative sizes.

2. Can the arithmetic mean ever be equal to the geometric mean?

Yes, in certain cases, the arithmetic mean and geometric mean can be equal. This happens when all the numbers in the set are the same. In this scenario, the arithmetic mean and geometric mean will both be equal to that number.

3. What is the significance of the arithmetic mean being greater than the geometric mean?

The arithmetic mean being greater than the geometric mean indicates that the values in the set are not evenly distributed. It implies that there are some values that are significantly larger than the others, resulting in a higher arithmetic mean. This can be useful in identifying outliers in a data set.

4. Can the arithmetic mean be used as a measure of central tendency in all cases?

No, the arithmetic mean may not always accurately represent the central tendency of a data set. This can happen when there are extreme outliers that significantly affect the arithmetic mean. In such cases, it may be more appropriate to use the median or mode as a measure of central tendency.

5. Are there any other instances where the arithmetic mean may not be greater than the geometric mean?

Yes, in certain distributions, such as bimodal distributions, the arithmetic mean may not be greater than the geometric mean. This happens when the values in the set are divided into two distinct groups with similar magnitudes, resulting in a smaller arithmetic mean.

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