- Thread starter
- #1

#### Petrus

##### Well-known member

- Feb 21, 2013

- 739

Decide area of the two function

\(\displaystyle y^2=x+1\) and \(\displaystyle y=-x+1\)

progress:

first I equal them to see where they intercept and get \(\displaystyle x=0\) and \(\displaystyle x=3\)

then I do integrate

\(\displaystyle \int_0^3 \sqrt{x+1}-(-x+1) = \frac{37}{6}\) which is not correct answer, What I am doing wrong?

Regards,

\(\displaystyle |\pi\rangle\)