- Thread starter
- #1
Petrus
Well-known member
- Feb 21, 2013
- 739
Hello MHB,
Decide area of the two function
\(\displaystyle y^2=x+1\) and \(\displaystyle y=-x+1\)
progress:
first I equal them to see where they intercept and get \(\displaystyle x=0\) and \(\displaystyle x=3\)
then I do integrate
\(\displaystyle \int_0^3 \sqrt{x+1}-(-x+1) = \frac{37}{6}\) which is not correct answer, What I am doing wrong?
Regards,
\(\displaystyle |\pi\rangle\)
Decide area of the two function
\(\displaystyle y^2=x+1\) and \(\displaystyle y=-x+1\)
progress:
first I equal them to see where they intercept and get \(\displaystyle x=0\) and \(\displaystyle x=3\)
then I do integrate
\(\displaystyle \int_0^3 \sqrt{x+1}-(-x+1) = \frac{37}{6}\) which is not correct answer, What I am doing wrong?
Regards,
\(\displaystyle |\pi\rangle\)