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#### xyz_1965

##### Member

- Jul 26, 2020

- 81

Use: area of segment = (area of sector OPQ) - (area of triangle OPQ).

Area of sector OPQ = (1/2)r^2(theta).

Area of triangle OPQ = (ab/2)(sin (theta)).

Solution:

Central angle is theta.

= 120°

= 2•pi/3 rad

Area of the shaded segment

= (Area of the sector) - (Area of the triangle)

= [(1/2) × 3^2 × (2•pi/3) - (1/2) × 3^2 × sin(120°)] cm^2

= [3•pi - (9/2) × sin(180° - 60°)] cm^2

= [3•pi - (9/2) × sin(60°)] cm^2

= [3•pi - (9/2) × (sqrt{3}/2)] cm^2

= [3•pi - (9/4)sqrt{3}] cm^2

= (3/4)[4•pi - 3sqrt{3}] cm^2

= 5.53 cm^2

You say?

Note: All work is done on paper prior to posting.