- #1
germangb
- 7
- 0
i have the following problem:
-an iron (7800kg/m3) body is submerged into in water (density = 1000kg/m3)
his weight in the air is 0,13N.
what i did is:
E=dVg (Push force, density of the liquid, volume of the body sumerged and gravity, respectively)
then:
the volume of the iron body is 0,000633m3, then:
E = 1000*0,000633g = 1,60
so, the the apparent weight is 0,13-1,60= -1,47N
______________________________
did I do it right?
-an iron (7800kg/m3) body is submerged into in water (density = 1000kg/m3)
his weight in the air is 0,13N.
what i did is:
E=dVg (Push force, density of the liquid, volume of the body sumerged and gravity, respectively)
then:
the volume of the iron body is 0,000633m3, then:
E = 1000*0,000633g = 1,60
so, the the apparent weight is 0,13-1,60= -1,47N
______________________________
did I do it right?