- Thread starter
- #1

- Jan 29, 2012

- 661

I have given a link to the topic there so the OP can see my response.Find arc length for the curve c(t)= (t,t,t^2) from 1<=t<=2?

I understand that I find C'(t) and integrate the length of it.

C'(t)= (1, 1, 2t) and so the length is sqrt{ 1 + 1 + 4t^2 } = sqrt{2+4t^2}

Now when integrating this....would I use the sqrt{ x^2 + a^2 } identity where x = 2t and a = sqrt{2}????

Help. Answer is (6-sqrt{3})/sqrt{2} + 1/2 log ( [2sqrt{2}+3]/[sqrt{2}+sqrt{3}] )