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I read in a differential geometry paper that Maxwell's equations can be formulated in terms of a connection on a Hermitian line bundle on Minkowski space.
I understand the derivation of the field strength 2 form,the proof that Maxwell's equations say that its exterior derivative is zero and its codifferential is the current density 1 form, and that there must exist a gauge potential whose exterior derivative equals the field strength.But how does the Arahnov-Bohm effect make this interpretation preferable? How is it reflected in this mathematical formulation?
I understand the derivation of the field strength 2 form,the proof that Maxwell's equations say that its exterior derivative is zero and its codifferential is the current density 1 form, and that there must exist a gauge potential whose exterior derivative equals the field strength.But how does the Arahnov-Bohm effect make this interpretation preferable? How is it reflected in this mathematical formulation?
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