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- #1

- Thread starter Yuuki
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- #1

- Mar 1, 2012

- 249

I would let \(\displaystyle u = x^2 \therefore du = 2x dx\)how do i go about integrating

\(\displaystyle \int x \cdot \sqrt{1-x^4}dx\)

i have no idea

\(\displaystyle \int x \cdot \sqrt{1-x^4} \cdot \dfrac{du}{2x} = \dfrac{1}{2} \int \sqrt{1-u^2} du\)

Do you know a trig sub for this integral?

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- Mar 1, 2012

- 249

Yes, that's the right sub to use. Are you ok going forward?u = sin(w) right?

thx!

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