- Thread starter
- #1
paulmdrdo
Active member
- May 13, 2013
- 386
∫(tan3x/sec2x)dx
this is what i do:
∫(tan3xsec-2x)dx
∫(tan2xtanxsec-1xsec-1x)dx
∫(sec2x-1)tanxsec-1xsec-1x)dx
let u = secx;
du = tanxsecxdx
now i'm stuck! please help.
this is what i do:
∫(tan3xsec-2x)dx
∫(tan2xtanxsec-1xsec-1x)dx
∫(sec2x-1)tanxsec-1xsec-1x)dx
let u = secx;
du = tanxsecxdx
now i'm stuck! please help.