Check your expansion of ##\vec r . \vec \omega ##.Pushoam said:
After correction:haruspex said:
Yes.Pushoam said:
But the angular momentum should be perpendicular to ## \vec r ##. Here, I am getting non-zero component in the direction of ##\hat r##.haruspex said:
The other term, ##\vec\omega##, also has a component in the direction of ##\vec r##. The two may cancel.Pushoam said:
Yes, it gets canceled.haruspex said:
Angular momentum is a physical quantity that measures the amount of rotational motion an object has. It is defined as the product of an object's moment of inertia and its angular velocity.
A rotating skew rod is a long, slender object that is rotating around an axis that is not aligned with its own axis of symmetry. This type of motion creates a complicated pattern of rotation and translation, making it a challenging problem in physics.
The angular momentum of a rotating skew rod can be calculated using the formula L = Iω, where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity. The moment of inertia can be found by integrating the rod's mass distribution with respect to its axis of rotation.
The angular momentum of a rotating skew rod is affected by its moment of inertia, angular velocity, and the distribution of its mass along its length. Other factors such as external torque and friction can also affect the rod's angular momentum.
The study of angular momentum of a rotating skew rod is important because it helps us understand the complex motion of objects in real-world scenarios, such as the rotation of a spinning top or the motion of a gyroscope. It is also a fundamental concept in physics and plays a key role in many areas of science and engineering.