Angular momentum in a rectangular box

In summary, the question is asking for a physical argument as to why the angular momentum of a classical particle about the center of a 3d box would not be conserved, unlike in a spherical well where orbital angular momentum is constant. The answer is that if the particle bounces off the sides of the box, the forces exerted by the walls are not central and thus the angular momentum is not conserved. This can also be seen by considering the combined system of the box and particle, where the box would start to spin if the particle bounces off the walls. Additionally, to prove that there are no states with both definite energy and definite orbital angular momentum magnitude, one can apply the angular momentum square operator to the energy eigenfunctions
  • #1
Mjolnir
6
0
This is more of a conceptual question. I'm looking for a "physical argument" as to why the angular momentum of a classical particle about the center of a 3d box wouldn't be conserved, as opposed to spherical well in which orbital angular momentum is a constant.
 
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  • #2
Mjolnir said:
This is more of a conceptual question. I'm looking for a "physical argument" as to why the angular momentum of a classical particle about the center of a 3d box wouldn't be conserved, as opposed to spherical well in which orbital angular momentum is a constant.

It depends what you mean by this. What are the forces on the particle? I am not sure if you mean a physical 3 d box which has a a gravitational pull on the particle, if the particle is inside or outside of the box, etc.

(nice handle...Thor's hammer if I remmeber correctly)
 
  • #3
by a 3d box I mean a potential well such that V(x,y,z) = 0 for -a/2 < x < a/2, -b/2 < y < b/2, and -c/2 < z < c/2; or V -> infinity otherwise

edit: glad you like the screen name :-)
 
  • #4
Mjolnir said:
by a 3d box I mean a potential well such that V(x,y,z) = 0 for -a/2 < x < a/2, -b/2 < y < b/2, and -c/2 < z < c/2; or V -> infinity otherwise

edit: glad you like the screen name :-)

But then the angular momentum is conserved as long as the particle does not touch the sides of the box, trivially.
If the particle bounces on the sides, then angular momentum is not conserved because the force exerted by the walls is not a central force (it's not along th eradius). Therefore, the change of momentum is not along the radius an dthe angular momentum is not conserved.

You can see this easily if you imagine the box to have a finite mass. when the particle bounces, the box would start to spin. Of course, the angular momentum of the combined system (box plus particle) would be conserved.
 
  • #5
To expand on this a bit, how would one go about using the time-independent Schrodinger equation to prove that there are no states with both definite energy and definite orbital angular momentum magnitude?
 
  • #6
Mjolnir said:
To expand on this a bit, how would one go about using the time-independent Schrodinger equation to prove that there are no states with both definite energy and definite orbital angular momentum magnitude?

Well, one way is to write the energy eigenfunctions (which are easy to write down since they are products of sine function) and then to apply the angular momentum square operator and show that these states are not eigenstates of L^2.
 

Related to Angular momentum in a rectangular box

What is angular momentum in a rectangular box?

Angular momentum is a physical quantity that describes the rotational motion of an object around an axis. In a rectangular box, this refers to the tendency of the box to rotate around its central axis.

How is angular momentum calculated in a rectangular box?

The angular momentum in a rectangular box can be calculated by multiplying the moment of inertia, which is a measure of the object's resistance to rotation, by the angular velocity, which is the rate at which the object is rotating.

What factors affect the angular momentum in a rectangular box?

The angular momentum in a rectangular box is affected by the mass distribution of the object, the shape of the box, and the angular velocity at which it is rotating.

What is the conservation of angular momentum in a rectangular box?

The conservation of angular momentum in a rectangular box states that the total angular momentum of the system remains constant, as long as there are no external torques acting on the box. This means that if the box is rotating at a certain speed, it will continue to rotate at that speed unless acted upon by an external force.

How is angular momentum in a rectangular box related to other types of momentum?

Angular momentum is a type of rotational momentum that is related to other types of linear momentum, such as linear momentum and energy. The principles of conservation of momentum and energy also apply to angular momentum in a rectangular box.

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