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I have posted a link there to this topic so the OP can see my work.Question on differential equations?

"Water flows in a rectangular tank with base area A at a constant rate of n units of volume per unit time. Water flows out of the tank through a hole at the bottom at a rate which is proportional to the square root of depth of water in the tank. It is found that the when depth is h, the level of water remain constant. Initially the tank is filled to a depth of 4h. Obtain a differential equation for the depth z at time t."

this is what i did so far(im not exactly sure what im doing... T_T) , please guide me in getting the answers:

dV/dt = k√(z)

z(0) = 4h

z(1)=h

[1/√(z)](dV/dt) =k

[1/√(z)] dV =k dt

integrate both sides,

ln √(z) + C = kt + C

i dont know what happens after this.. help