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- #1

- Thread starter tmt
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- Thread starter
- #1

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- #2

- Jan 26, 2012

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Did you mean, how do you get from $2(x^{2}+y^{2})(2x+2yy')$ to $4x(x^{2}+y^{2})+4y(x^{2}+y^{2})y'$? Because, if so, that's just distributing the $(x^{2}+y^{2})$ times the other stuff in parentheses.Hi working on an algebra/calculus problem

How do I get from

2 (x2+y2) (2x+2yy')

to 4x (x2+y2) + 4y(x2+y2) y'

It is very confusing.

Tim

- Thread starter
- #3

Did you mean, how do you get from $2(x^{2}+y^{2})(2x+2yy')$ to $4x(x^{2}+y^{2})+4y(x^{2}+y^{2})y'$? Because, if so, that's just distributing the $(x^{2}+y^{2})$ times the other stuff in parentheses.

Yes I did,

Thank you!