- Thread starter
- #1
Did you mean, how do you get from $2(x^{2}+y^{2})(2x+2yy')$ to $4x(x^{2}+y^{2})+4y(x^{2}+y^{2})y'$? Because, if so, that's just distributing the $(x^{2}+y^{2})$ times the other stuff in parentheses.Hi working on an algebra/calculus problem
How do I get from
2 (x2+y2) (2x+2yy')
to 4x (x2+y2) + 4y(x2+y2) y'
It is very confusing.
Tim
Did you mean, how do you get from $2(x^{2}+y^{2})(2x+2yy')$ to $4x(x^{2}+y^{2})+4y(x^{2}+y^{2})y'$? Because, if so, that's just distributing the $(x^{2}+y^{2})$ times the other stuff in parentheses.